2020 WAEC chemistry Practical Expo/Runs (Questions And Answer)

Free 2020 WAEC Expo | 2020 WAEC Runs (Runz) |2020/2021 WAEC QUESTIONS & ANSWERS

2020 WAEC chemistry practical expo/runs (questions and answer) Correct 2020/2021 chemistry practical expo answers. With guarantee, you will get your verified chemistry practical answers before exam time. Not only biology practicals, rather to all your waec subjects.

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44 thoughts on “2020 WAEC chemistry Practical Expo/Runs (Questions And Answer)

  1. Please send the chemistry practical questions and answer this night I beg don’t send it tomorrow in when I’ve started send it very early in the morning or this night abeg help me out

  2. Nice one boss …dis is how naijaloaded got popular doing free waec question an ans…more power to u …I have click 10x but I did not see any tin

  3. LEASE REMEMBER TO USE YOUR’S SCHOOL’S AVERAGE TITRE VALUE(AVERAGE VOLUME OF ACID). WE USED 15.26cm3, TRY TO KNOW YOUR SCHOOL’S AVERAGE TITRE VALUE. ASK YOUR CHEMISTRY TEACHER. THEN, ANYWHERE YOU SEE 15.26cm3 IN MY CALCULATION, PUT YOUR SCHOOL’S OWN AND RE-CALCULATE. THIS IS VERY IMPORTANT!!!

    (1a)
    In a tabular form

    Burette Reading|1st reading|2nd reading|3rd reading
    Final |15.25|0.00|45.79|
    Initial|0.00||15.25|30.53|
    Volume of acid used |15.25|15.28|15.26

    Average volume of acid used = 15.25 + 15.26/2
    = 15.255cm³
    =15.26cm³

    (1bi)
    Given: Mass of conc of A = 5g/500cm³ = 5g/0.5dm³
    Ca = 10g/dm³

    A is HNO3
    Therefore; Molar mass = 1+14+(16×3)
    = 15+48
    =63g/mol

    Molarity of A = gram conc/molar mass
    Ca = 10/63 = 0.1587mol/dm³

    (1bii)
    Using CaVa/CbVb = nA/nB
    With reacting equation:
    HNO3 +NaOH–>NaNO3 + H2O
    nA = 1, nB = 1
    0.1587×15.26/Cb×25.00 = 1/1
    25Cb = 0.1587×15.26
    CB = 0.1587×15.26/25
    CB = 0.09687mol/dm³

    (1biii)
    B is NaOH
    Molar mass = 23+16+1
    =40g/mol
    Conc of B in g/dm³ = molarity×molar mass
    =0.09687×40
    =3.8748g/dm³

    (1biv)
    No of moles present in 250cm³ of NaOH is
    = molar conc. × volume
    = 0.09687 × 250/1000
    = 0.0242 moles

    Mole ratio of NaOH and NaNO3 is 1:1
    No of moles of NaNO3 which reacted is 0.0242
    Mass of NaNO3 formed = molar mass × no of moles
    = 85 × 0.0242
    =2.057grams

  4. Please send me economics 2020 waec (theory and objectives)please send it before 5pm today, please I no wan fail oooo

  5. Call Mr Daniel now on 0810 018 4817 for your waec 2020 theory, essays, practical questions and answers directly to your cell phone, whatsapp or mail ✉

  6. Please Sir I need Physical Practical this might or now and please don’t send it when I’m already at the laboratory. Please send the Answer and Questions so that I can work on it before tommorow please. God Bless you 🙏🙏

  7. Pls help me for literature English waec questions and solution for tomorrow 21st of August I don’t want to fail

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